6-4x-4.9x^2=0

Solution for 6-4x-4.9x^2=0 equation:

6-4x-4.9x^2=0

a = -4.9; b = -4; c = +6;
Δ = b2-4ac
Δ = -42-4·(-4.9)·6
Δ = 133.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{133.6}}{2*-4.9}=\frac{4-\sqrt{133.6}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{133.6}}{2*-4.9}=\frac{4+\sqrt{133.6}}{-9.8}
$